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3w^2+w-844=0
a = 3; b = 1; c = -844;
Δ = b2-4ac
Δ = 12-4·3·(-844)
Δ = 10129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{10129}}{2*3}=\frac{-1-\sqrt{10129}}{6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{10129}}{2*3}=\frac{-1+\sqrt{10129}}{6} $
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